TSTP Solution File: ITP033^1 by Duper---1.0
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% File : Duper---1.0
% Problem : ITP033^1 : TPTP v8.1.2. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:38:26 EDT 2023
% Result : Theorem 4.83s 5.01s
% Output : Proof 4.83s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.15 % Problem : ITP033^1 : TPTP v8.1.2. Released v7.5.0.
% 0.13/0.16 % Command : duper %s
% 0.15/0.38 % Computer : n007.cluster.edu
% 0.15/0.38 % Model : x86_64 x86_64
% 0.15/0.38 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.38 % Memory : 8042.1875MB
% 0.15/0.38 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.38 % CPULimit : 300
% 0.15/0.38 % WCLimit : 300
% 0.15/0.38 % DateTime : Sun Aug 27 10:36:42 EDT 2023
% 0.15/0.38 % CPUTime :
% 4.83/5.01 SZS status Theorem for theBenchmark.p
% 4.83/5.01 SZS output start Proof for theBenchmark.p
% 4.83/5.01 Clause #1 (by assumption #[]): Eq (binary1721989714Tree_a h (binary717961607le_T_a t1 x t2)) True
% 4.83/5.01 Clause #3 (by assumption #[]): Eq
% 4.83/5.01 (∀ (H : a → int) (T1 : binary1439146945Tree_a) (X : a) (T2 : binary1439146945Tree_a),
% 4.83/5.01 binary1721989714Tree_a H (binary717961607le_T_a T1 X T2) → binary1721989714Tree_a H T1)
% 4.83/5.01 True
% 4.83/5.01 Clause #272 (by assumption #[]): Eq (Not (binary1721989714Tree_a h t1)) True
% 4.83/5.01 Clause #273 (by clausification #[272]): Eq (binary1721989714Tree_a h t1) False
% 4.83/5.01 Clause #340 (by clausification #[3]): ∀ (a_1 : a → int),
% 4.83/5.01 Eq
% 4.83/5.01 (∀ (T1 : binary1439146945Tree_a) (X : a) (T2 : binary1439146945Tree_a),
% 4.83/5.01 binary1721989714Tree_a a_1 (binary717961607le_T_a T1 X T2) → binary1721989714Tree_a a_1 T1)
% 4.83/5.01 True
% 4.83/5.01 Clause #341 (by clausification #[340]): ∀ (a_1 : a → int) (a_2 : binary1439146945Tree_a),
% 4.83/5.01 Eq
% 4.83/5.01 (∀ (X : a) (T2 : binary1439146945Tree_a),
% 4.83/5.01 binary1721989714Tree_a a_1 (binary717961607le_T_a a_2 X T2) → binary1721989714Tree_a a_1 a_2)
% 4.83/5.01 True
% 4.83/5.01 Clause #342 (by clausification #[341]): ∀ (a_1 : a → int) (a_2 : binary1439146945Tree_a) (a : a),
% 4.83/5.01 Eq
% 4.83/5.01 (∀ (T2 : binary1439146945Tree_a),
% 4.83/5.01 binary1721989714Tree_a a_1 (binary717961607le_T_a a_2 a T2) → binary1721989714Tree_a a_1 a_2)
% 4.83/5.01 True
% 4.83/5.01 Clause #343 (by clausification #[342]): ∀ (a_1 : a → int) (a_2 : binary1439146945Tree_a) (a : a) (a_3 : binary1439146945Tree_a),
% 4.83/5.01 Eq (binary1721989714Tree_a a_1 (binary717961607le_T_a a_2 a a_3) → binary1721989714Tree_a a_1 a_2) True
% 4.83/5.01 Clause #344 (by clausification #[343]): ∀ (a_1 : a → int) (a_2 : binary1439146945Tree_a) (a : a) (a_3 : binary1439146945Tree_a),
% 4.83/5.01 Or (Eq (binary1721989714Tree_a a_1 (binary717961607le_T_a a_2 a a_3)) False)
% 4.83/5.01 (Eq (binary1721989714Tree_a a_1 a_2) True)
% 4.83/5.01 Clause #345 (by superposition #[344, 1]): Or (Eq (binary1721989714Tree_a (fun x => h x) t1) True) (Eq False True)
% 4.83/5.01 Clause #1019 (by betaEtaReduce #[345]): Or (Eq (binary1721989714Tree_a h t1) True) (Eq False True)
% 4.83/5.01 Clause #1020 (by clausification #[1019]): Eq (binary1721989714Tree_a h t1) True
% 4.83/5.01 Clause #1021 (by superposition #[1020, 273]): Eq True False
% 4.83/5.01 Clause #1031 (by clausification #[1021]): False
% 4.83/5.01 SZS output end Proof for theBenchmark.p
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